One Step Equation Review Period 2 Question Preview (ID: 60951)


Soling One Step Equations. TEACHERS: click here for quick copy question ID numbers.

Solve: x - 5 = 7
a) 2
b) 12
c) -2
d) -12

Solve: x + 4 = 13
a) 9
b) -17
c) -9
d) 17

Solve: -3 + a = -11
a) 8
b) 14
c) -8
d) -14

To solve x + 5 = 9, you would ______________________.
a) Add 5 to both sides.
b) Add 9 to both sides.
c) Subtract 5 from both sides.
d) Subtract 5 from both sides.

To solve -7 + b = -4, you would ______________________.
a) Add 7 to both sides.
b) Subtract 7 from both sides.
c) Add 4 to both sides.
d) Add 4 to both sides.

To solve c - 20 = -5, you would ______________________.
a) Add 5 to both sides.
b) Subtract 5 from both sides.
c) Add 20 to both sides.
d) Subtract 20 from both sides.

Solve: -12 + c = -15, you would______________.
a) Add 15 to both sides.
b) Subtract 15 from both sides.
c) Add 12 to both sides.
d) Subtract 12 from both sides.

Solve: -12 + c = -15
a) -27
b) 27
c) -3
d) 3

Solve: d - 100 = 99
a) d = -1
b) d = 1
c) d = 199
d) d = -199

Solve: c - 50 = -6
a) c = -56
b) c = -44
c) c = 56
d) c = 44

To solve t /9 = -10, you would ______________________.
a) Add 10 to both sides.
b) Subtract 10 from both sides.
c) multiply both sides by 9.
d) Divide both sides by 9.

Solve t/9 = -10
a) 90
b) -90
c) 19
d) -19

To solve 5x = 25, you would ______________________.
a) Add 5 to both sides
b) subtract both sides by 5
c) multiply both sides by 5
d) Divide both sides by 5

Solve 5x - 25
a) x= 20
b) x= 5
c) x=30
d) c= -5

To solve - -30 = -5x, you would ______________________.
a) Add 5 to both sides
b) Divide both sides by 5
c) Divide both sides by -5
d) Multiply both sides by -5

Solve - -30 = -5x
a) x= 35
b) x= 30
c) x = 6
d) x = -6

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