Solving Equations With Variables Both Sides With Special Cases Question Preview (ID: 52513)


Determine If There Is One, No, Or Infinite Solutions. TEACHERS: click here for quick copy question ID numbers.

−5 + 5(x − 7) = −40 + 5x
a) Infinite Solutions
b) No Solution
c) x=-5
d) x=-1

6x + 1 = −6(1 − x)
a) No Solution
b) Infinite Solutions
c) x=2
d) x=-2

−8(1 + 4x) + 7x = −25 − 8x
a) x=1
b) x=-1
c) No Solution
d) Infinite Solutions

8x − 6 = 6(x + 3) + 6x
a) x=-6
b) x=6
c) No Solution
d) Infinite Solutions

3(x + 1) - 5 = 3x - 2
a) Infinite Solutions
b) No Solution
c) x=4/3
d) x=-4/3

-8(x + 1) + 3(x - 2) = -3x + 2
a) x=-8
b) x=8
c) Infinite Solutions
d) No Solution

2 + 2/5x = 3/8x − 1
a) x=-120
b) x=40
c) Infinite Solutions
d) No Solution

3x + 8 = 3(4 + x) − 4
a) Infinite Solutions
b) No Solution
c) x=0
d) x=8

− 3(2x + 1) + 4(2x − 3) = 2x − 15
a) Infinite Solutions
b) No Solution
c) x=-15
d) x=4

− (2x − 1) − 2x = 4(1 − x)
a) No Solution
b) Infinite Solutions
c) x=-4
d) x=1

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