Remarkable Identities Question Preview (ID: 50478)


This Game Aims To Review The Remarkable Identities Course For Grade 8 Students. TEACHERS: click here for quick copy question ID numbers.

x2 – 6x + 9 =
a) (x-3)^2
b) (x+3)^2
c) -5x + 9
d) (x-3)(x+3)

(x+2)(-3x+5)=
a) 3x2-x+10
b) -3x2-x+10
c) -3x2+x+10
d) 3x2 –x +10

The factorized form of: (x-5)^2-2(x-5)(x+1) is:
a) -(x-5)(x+7)
b) (x-5)(-x-3)
c) -6(x-5)
d) 4x2-2x+1

If f(x) = x2 - 6x - 9 Then f(-3)=
a) 0
b) -2
c) 18
d) 15

(61)2-(59)2=
a) 2
b) 120
c) 240
d) 4

9x2 - 1=
a) (3x-1)(3x+1)
b) (x+3)(x-3)
c) (3x-1)2
d) (9x+1)(9x-1)

(x-5)2-2=
a) x2+10x+23
b) x2-10x+23
c) x2-10x-27
d) x2+10x+27

The factorized form among the following is:
a) (x-3)+(2x-5)
b) (3-x)(2x-5)
c) (x-3)2 - 2(2x+5)
d) X2 – 2x + 3

(2x+y)2 - (2x-y)2 =
a) 4xy
b) (2x+y)(2x-y)
c) 2x(2x-y)2
d) 8xy

(5x+2)2-3x(10x+4)=
a) (5x+2)(x+2)
b) (5x+2)(-x+2)
c) (10x+4)(-x+2)
d) (10x+4)(x-2)

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