Solving Systems By Substitution Question Preview (ID: 41547)


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y = 5x + 2 and y = 4x - 3
a) (-5, -23)
b) (-5, 27)
c) (-1, -5)
d) (-1, -7)

y = -2x - 10 and 3x - 5y = -15
a) (-5, 0)
b) no solution
c) (0, 5)
d) (-2, 0)

y = 2x + 8 and y = 5x - 1
a) (3, 14)
b) (-3, 2)
c) (1, 10)
d) (-1, 6)

y = 3x + 2 and x + 2y = 11
a) (1, 5)
b) (3, 11)
c) (-1, -1)
d) (-3, -7)

y = 2x - 3 and x + 3y = 5
a) (2, 1)
b) (1, -1)
c) (-2, -7)
d) (-1, -5)

y = 4x - 4 and 3x - 4y = -10
a) (2, 4)
b) (-2, 4)
c) (2, -4)
d) (-2, -4)

y = -3x - 7 and 2x + 6y = -10
a) (-2, -1)
b) (1, -2)
c) (-2, 1)
d) (2, 1)

y = -2x - 15 and 2x - 4y = 10
a) (-5, -5)
b) (2, 5)
c) (-2, 5)
d) (-5, -2)

y = 2x + 5 and 5x - 3y = -10
a) (-5, -5)
b) (-5, 5)
c) (5, -5)
d) (5, 3)

y = x - 1 and 2x - 3y = -1
a) (4, 3)
b) (-4, 3)
c) (4, -3)
d) (-4, -3)

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