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Given y = 2x², the equation for the line of symmetry for this graph is
quadratic
( - 4, - 1)
parabolic graph
U-shape
The graph will open outward.
x = 0
imaginary roots
It has a minimum turning point.
Given y = 2(x-1)² +1, what is kind of graph is this?
quadratic
( - 4, - 1)
parabolic graph
U-shape
The graph will open outward.
x = 0
imaginary roots
It has a minimum turning point.
Which of the following is True of y = x²?
quadratic
( - 4, - 1)
parabolic graph
U-shape
The graph will open outward.
x = 0
imaginary roots
It has a minimum turning point.
In standard form, a _______ function is written as y = ax² + bx + c
quadratic
( - 4, - 1)
parabolic graph
U-shape
The graph will open outward.
x = 0
imaginary roots
It has a minimum turning point.
Given y = 3x², what will happen to the graph when the coefficient of x² becomes 1?
quadratic
( - 4, - 1)
parabolic graph
U-shape
The graph will open outward.
x = 0
imaginary roots
It has a minimum turning point.
This curve, y=x² - 5x + 7, has what kind of roots?
quadratic
( - 4, - 1)
parabolic graph
U-shape
The graph will open outward.
x = 0
imaginary roots
It has a minimum turning point.
What is the general shape of parabolas?
quadratic
( - 4, - 1)
parabolic graph
U-shape
The graph will open outward.
x = 0
imaginary roots
It has a minimum turning point.
Given y = 2(x + 4)² -1, the coordinates of the turning point are
quadratic
( - 4, - 1)
parabolic graph
U-shape
The graph will open outward.
x = 0
imaginary roots
It has a minimum turning point.
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