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Which of the following is not a physical property?
suspensions
flammability
have different isotopes
2.3 kg
Cm
Mass of new substances equals mass of original materials.
150,000,000,000
To solve a problem or better understand an observation
Combining 2.5kg of A with 1.5kg of B creates new substances with different properties.
suspensions
flammability
have different isotopes
2.3 kg
Cm
Mass of new substances equals mass of original materials.
150,000,000,000
To solve a problem or better understand an observation
The distance between the Earth and the Sun is about 1.5 x 1011 m. In standard notation?
suspensions
flammability
have different isotopes
2.3 kg
Cm
Mass of new substances equals mass of original materials.
150,000,000,000
To solve a problem or better understand an observation
Which of the following can be separated into its components with a filter?
suspensions
flammability
have different isotopes
2.3 kg
Cm
Mass of new substances equals mass of original materials.
150,000,000,000
To solve a problem or better understand an observation
Which of these groups of letters could be used as a symbol for a single element?
suspensions
flammability
have different isotopes
2.3 kg
Cm
Mass of new substances equals mass of original materials.
150,000,000,000
To solve a problem or better understand an observation
Atoms of elements whose atomic mass is shown as a decimal in the periodic table
suspensions
flammability
have different isotopes
2.3 kg
Cm
Mass of new substances equals mass of original materials.
150,000,000,000
To solve a problem or better understand an observation
What is the main purpose of the scientific method?
suspensions
flammability
have different isotopes
2.3 kg
Cm
Mass of new substances equals mass of original materials.
150,000,000,000
To solve a problem or better understand an observation
If you measured 2,300 grams, how many kilograms did you measure?
suspensions
flammability
have different isotopes
2.3 kg
Cm
Mass of new substances equals mass of original materials.
150,000,000,000
To solve a problem or better understand an observation
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