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Scenario D: Find the area of only the sidewalk.
(s + 9)(s - 2) = 102
2(x + 5) + 2(x + 6)
(2x + 5)(2x + 6) = 72
w = 17, L = 6
w = 7, L = 12
(x + 3)(x + 10) = 60
42
L = w + 5, L(w) = 84
Scenario J: Write and equation that could be used to find the length of one of the original sides.
(s + 9)(s - 2) = 102
2(x + 5) + 2(x + 6)
(2x + 5)(2x + 6) = 72
w = 17, L = 6
w = 7, L = 12
(x + 3)(x + 10) = 60
42
L = w + 5, L(w) = 84
Scenario J: Find the dimensions of the new rectangle.
(s + 9)(s - 2) = 102
2(x + 5) + 2(x + 6)
(2x + 5)(2x + 6) = 72
w = 17, L = 6
w = 7, L = 12
(x + 3)(x + 10) = 60
42
L = w + 5, L(w) = 84
Scenario H: Write a system of equations that can be used to find the length and width of the rectangle.
(s + 9)(s - 2) = 102
2(x + 5) + 2(x + 6)
(2x + 5)(2x + 6) = 72
w = 17, L = 6
w = 7, L = 12
(x + 3)(x + 10) = 60
42
L = w + 5, L(w) = 84
Scenario D: Write an expression to represent the perimeter of the LARGER rectangle.
(s + 9)(s - 2) = 102
2(x + 5) + 2(x + 6)
(2x + 5)(2x + 6) = 72
w = 17, L = 6
w = 7, L = 12
(x + 3)(x + 10) = 60
42
L = w + 5, L(w) = 84
Scenario D: Write an equation to find the area of the LARGER rectangle.
(s + 9)(s - 2) = 102
2(x + 5) + 2(x + 6)
(2x + 5)(2x + 6) = 72
w = 17, L = 6
w = 7, L = 12
(x + 3)(x + 10) = 60
42
L = w + 5, L(w) = 84
Scenario K: Write and equation to find x, the amount added to each dimension.
(s + 9)(s - 2) = 102
2(x + 5) + 2(x + 6)
(2x + 5)(2x + 6) = 72
w = 17, L = 6
w = 7, L = 12
(x + 3)(x + 10) = 60
42
L = w + 5, L(w) = 84
Scenario H: Find the length and width of the rectangle.
(s + 9)(s - 2) = 102
2(x + 5) + 2(x + 6)
(2x + 5)(2x + 6) = 72
w = 17, L = 6
w = 7, L = 12
(x + 3)(x + 10) = 60
42
L = w + 5, L(w) = 84
Check it!