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Calculator Practice And Molar Conversions
Test Description: Practice calculations with scientific notation and molar conversions.
Instructions: Answer all questions to get your test result.
1) Solve the following calculation: (1.25x10^23 atoms Mg)(1 mol Mg / 6.02x10^23 atoms Mg)
A
217302 mol Mg
B
2.08x10^45 mol Mg
C
0.21 mol Mg
D
21 mol Mg
2) Solve the following calculation: (60 g Ne)(1 mol Ne / 20.2 g Ne)(6.02x10^23 atoms Ne / 1 mol Ne)
A
1.79x10^24 atoms Ne
B
17.9 atoms Ne
C
179 g Ne
D
1.79 mol Ne
3) Solve the following calculation: (3.24x10^22 atoms Al)(1 mol Al / 6.02x10^23 atoms Al)(27 g Al / 1 mol Al)
A
145 g Al
B
1.45x10^46 atoms Al
C
1.45x10^46 g Al
D
1.45 g Al
4) Solve the following calculation: (3.2 mol C)(6.02x10^23 atoms C / 1 mol C)
A
1.93x10^24 atoms C
B
1.93 atoms C
C
193 atoms C
D
1.93 mol C
5) How many moles are there in 7.5x10^23 atoms of sulfur?
A
1.25x10^46 mol S
B
2.34x10^22 mol S
C
12.5 mol S
D
1.25 mol S
6) How many moles are there in 450 grams of sodium?
A
1.96 mol Na
B
0.1957 mol Na
C
10350 mol Na
D
19.57 mol Na
7) How many grams are there in 2.3x10^24 atoms of silver?
A
412 g Ag
B
4.12x10^48 g Ag
C
1.45x10^46 g Al
D
41.2 g Ag
8) How many grams are there in 9.4x10^25 molecules of hydrogen gas?
A
1.57x10^48 g hydrogen gas
B
315 g hydrogen gas
C
157 g hydrogen gas
D
3.15x10^48 g hydrogen gas
9) How many grams are there in 4.5 moles of barium nitrite?
A
1976 g barium nitrite
B
1032 g barium nitrite
C
680 g barium nitrite
D
824 g barium nitrite
10) How many molecules are there in 9.34 grams of dihydrogen monoxide?
A
312 molecules dihydrogen monoxide
B
3.12 molecules dihydrogen monoxide
C
0.518 molecules dihydrogen monoxide
D
3.12x10^23 molecules dihydrogen monoxide
*select an answer for all questions
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