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Which half-reaction correctly represents reduction?
Two electrons are lost.
Fe^2+ + 2e- --> Fe^0
Na2S
Br2 +Hg --> Hg^2+ + 2Br-
anode, which is positive
Br2^0 + 2e- --> 2Br-
Cu^2+(aq) + 2e- --> Cu(s)
Cu + 2Ag+ + 2NO3^- --> 2Ag + Cu^2+ + 2NO3^-
Which change occures when an Sn^2+ ion is oxidized?
Two electrons are lost.
Fe^2+ + 2e- --> Fe^0
Na2S
Br2 +Hg --> Hg^2+ + 2Br-
anode, which is positive
Br2^0 + 2e- --> 2Br-
Cu^2+(aq) + 2e- --> Cu(s)
Cu + 2Ag+ + 2NO3^- --> 2Ag + Cu^2+ + 2NO3^-
In an electrolytic cell, oxidation takes place at the
Two electrons are lost.
Fe^2+ + 2e- --> Fe^0
Na2S
Br2 +Hg --> Hg^2+ + 2Br-
anode, which is positive
Br2^0 + 2e- --> 2Br-
Cu^2+(aq) + 2e- --> Cu(s)
Cu + 2Ag+ + 2NO3^- --> 2Ag + Cu^2+ + 2NO3^-
Which redox equation is correctly balanced?
Two electrons are lost.
Fe^2+ + 2e- --> Fe^0
Na2S
Br2 +Hg --> Hg^2+ + 2Br-
anode, which is positive
Br2^0 + 2e- --> 2Br-
Cu^2+(aq) + 2e- --> Cu(s)
Cu + 2Ag+ + 2NO3^- --> 2Ag + Cu^2+ + 2NO3^-
Which half-reaction correctly represents a reduction reaction?
Two electrons are lost.
Fe^2+ + 2e- --> Fe^0
Na2S
Br2 +Hg --> Hg^2+ + 2Br-
anode, which is positive
Br2^0 + 2e- --> 2Br-
Cu^2+(aq) + 2e- --> Cu(s)
Cu + 2Ag+ + 2NO3^- --> 2Ag + Cu^2+ + 2NO3^-
Given the reaction: Ca(s) + Cu^2+(aq) --> Ca^2+(aq) + Cu(s). What is the correct reduction half-reaction?
Two electrons are lost.
Fe^2+ + 2e- --> Fe^0
Na2S
Br2 +Hg --> Hg^2+ + 2Br-
anode, which is positive
Br2^0 + 2e- --> 2Br-
Cu^2+(aq) + 2e- --> Cu(s)
Cu + 2Ag+ + 2NO3^- --> 2Ag + Cu^2+ + 2NO3^-
In which compound does sulfur have an oxidation number of -2?
Two electrons are lost.
Fe^2+ + 2e- --> Fe^0
Na2S
Br2 +Hg --> Hg^2+ + 2Br-
anode, which is positive
Br2^0 + 2e- --> 2Br-
Cu^2+(aq) + 2e- --> Cu(s)
Cu + 2Ag+ + 2NO3^- --> 2Ag + Cu^2+ + 2NO3^-
Which equation represents a redox reaction?
Two electrons are lost.
Fe^2+ + 2e- --> Fe^0
Na2S
Br2 +Hg --> Hg^2+ + 2Br-
anode, which is positive
Br2^0 + 2e- --> 2Br-
Cu^2+(aq) + 2e- --> Cu(s)
Cu + 2Ag+ + 2NO3^- --> 2Ag + Cu^2+ + 2NO3^-
Check it!