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Match it!
Match it! Select the correct answer from the pull down...Good luck!
vchbfdtghy
dfgdfbv
tyygvffd
Hooke
F = kx
cccng
0.90 m
0.60 J
6.0 N/0.090 m
A spring is suspended from a bar. When a load of 6N is added to the bottom of the spring, it's length changes from 0.040 m to 0.13 m. To find the spring constant of the spring you would use
dfgdfbv
tyygvffd
Hooke
F = kx
cccng
0.90 m
0.60 J
6.0 N/0.090 m
The energy stored in the spring when a force of 2N is applied
dfgdfbv
tyygvffd
Hooke
F = kx
cccng
0.90 m
0.60 J
6.0 N/0.090 m
A force of 2N extends a spring by 0.30 m. A force of 6.0 N force will extend the spring by
dfgdfbv
tyygvffd
Hooke
F = kx
cccng
0.90 m
0.60 J
6.0 N/0.090 m
weeefcfg
dfgdfbv
tyygvffd
Hooke
F = kx
cccng
0.90 m
0.60 J
6.0 N/0.090 m
A well-known law states The extension of a spring is proportional to the force causing the extension is known as:
dfgdfbv
tyygvffd
Hooke
F = kx
cccng
0.90 m
0.60 J
6.0 N/0.090 m
Which expression representes Hook's law?
dfgdfbv
tyygvffd
Hooke
F = kx
cccng
0.90 m
0.60 J
6.0 N/0.090 m
fdgjhtyngfhg
dfgdfbv
tyygvffd
Hooke
F = kx
cccng
0.90 m
0.60 J
6.0 N/0.090 m
Check it!