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A local marathon had thirteen thousand, three hundred seventy-three participants last year. What is this number in standard form?
56,739
13,373
6 x 7 = 42, so 6 x 70 = 420
19,939
30,000 + 1,000 + 400 + 90 + 8
19,439
49,400
The 6 in 798,671 is 10 times the value of the 6 in 514,069
A number has a 6 in the thousands place and a 3 in the tens place. Which could be this number?
56,739
13,373
6 x 7 = 42, so 6 x 70 = 420
19,939
30,000 + 1,000 + 400 + 90 + 8
19,439
49,400
The 6 in 798,671 is 10 times the value of the 6 in 514,069
Which shows the correct expanded form of 31,498
56,739
13,373
6 x 7 = 42, so 6 x 70 = 420
19,939
30,000 + 1,000 + 400 + 90 + 8
19,439
49,400
The 6 in 798,671 is 10 times the value of the 6 in 514,069
In which of the following is the value of one digit ten times the value of the digit to its right?
56,739
13,373
6 x 7 = 42, so 6 x 70 = 420
19,939
30,000 + 1,000 + 400 + 90 + 8
19,439
49,400
The 6 in 798,671 is 10 times the value of the 6 in 514,069
Which strategy could help you solve 6 x 70?
56,739
13,373
6 x 7 = 42, so 6 x 70 = 420
19,939
30,000 + 1,000 + 400 + 90 + 8
19,439
49,400
The 6 in 798,671 is 10 times the value of the 6 in 514,069
What is 49,381 rounded to the nearest hundred?
56,739
13,373
6 x 7 = 42, so 6 x 70 = 420
19,939
30,000 + 1,000 + 400 + 90 + 8
19,439
49,400
The 6 in 798,671 is 10 times the value of the 6 in 514,069
Which of the following statements is correct?
56,739
13,373
6 x 7 = 42, so 6 x 70 = 420
19,939
30,000 + 1,000 + 400 + 90 + 8
19,439
49,400
The 6 in 798,671 is 10 times the value of the 6 in 514,069
In which of the following is the value of the 3 the least?
56,739
13,373
6 x 7 = 42, so 6 x 70 = 420
19,939
30,000 + 1,000 + 400 + 90 + 8
19,439
49,400
The 6 in 798,671 is 10 times the value of the 6 in 514,069
Check it!