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Hook’s law is written as :
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Stffness constant
None of the choices
T = K ∆l
Frictiona; force
Proportional to the elongation of the spring
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When a body is in equilibrium under the action of the forces , These two forces have:
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Stffness constant
None of the choices
T = K ∆l
Frictiona; force
Proportional to the elongation of the spring
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The force is characterized by
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Stffness constant
None of the choices
T = K ∆l
Frictiona; force
Proportional to the elongation of the spring
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Weight of a body is
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Stffness constant
None of the choices
T = K ∆l
Frictiona; force
Proportional to the elongation of the spring
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The tension of a spring is :
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Stffness constant
None of the choices
T = K ∆l
Frictiona; force
Proportional to the elongation of the spring
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K represents in Hook’s law
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Stffness constant
None of the choices
T = K ∆l
Frictiona; force
Proportional to the elongation of the spring
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One of these forces is contact force
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Stffness constant
None of the choices
T = K ∆l
Frictiona; force
Proportional to the elongation of the spring
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1 N/cm is equivalent to
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Stffness constant
None of the choices
T = K ∆l
Frictiona; force
Proportional to the elongation of the spring
All choices
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