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The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 121?
To find the area or percentage between the given value and mean
z=(121-100)/15=21/15= 1.40
Subtract
z=(72-100)/15=-28/15=-1.87
z=(140-100)/15=40/15= 2.67
Divide
z=( 100-100)/15= 0/15= 0
A number that tells you how many standard deviations from mean of set
How do you find the number of standard deviations that would fit into the distance found?
To find the area or percentage between the given value and mean
z=(121-100)/15=21/15= 1.40
Subtract
z=(72-100)/15=-28/15=-1.87
z=(140-100)/15=40/15= 2.67
Divide
z=( 100-100)/15= 0/15= 0
A number that tells you how many standard deviations from mean of set
The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 100?
To find the area or percentage between the given value and mean
z=(121-100)/15=21/15= 1.40
Subtract
z=(72-100)/15=-28/15=-1.87
z=(140-100)/15=40/15= 2.67
Divide
z=( 100-100)/15= 0/15= 0
A number that tells you how many standard deviations from mean of set
The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 140?
To find the area or percentage between the given value and mean
z=(121-100)/15=21/15= 1.40
Subtract
z=(72-100)/15=-28/15=-1.87
z=(140-100)/15=40/15= 2.67
Divide
z=( 100-100)/15= 0/15= 0
A number that tells you how many standard deviations from mean of set
How is a z-score used?
To find the area or percentage between the given value and mean
z=(121-100)/15=21/15= 1.40
Subtract
z=(72-100)/15=-28/15=-1.87
z=(140-100)/15=40/15= 2.67
Divide
z=( 100-100)/15= 0/15= 0
A number that tells you how many standard deviations from mean of set
What is a Z-score?
To find the area or percentage between the given value and mean
z=(121-100)/15=21/15= 1.40
Subtract
z=(72-100)/15=-28/15=-1.87
z=(140-100)/15=40/15= 2.67
Divide
z=( 100-100)/15= 0/15= 0
A number that tells you how many standard deviations from mean of set
The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 72?
To find the area or percentage between the given value and mean
z=(121-100)/15=21/15= 1.40
Subtract
z=(72-100)/15=-28/15=-1.87
z=(140-100)/15=40/15= 2.67
Divide
z=( 100-100)/15= 0/15= 0
A number that tells you how many standard deviations from mean of set
How do you find the distance from the given value and the mean?
To find the area or percentage between the given value and mean
z=(121-100)/15=21/15= 1.40
Subtract
z=(72-100)/15=-28/15=-1.87
z=(140-100)/15=40/15= 2.67
Divide
z=( 100-100)/15= 0/15= 0
A number that tells you how many standard deviations from mean of set
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