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How is a z-score used?
A number that tells you how many standard deviations from mean of set
Subtract
z=(121-100)/15=21/15= 1.40
True
Divide
z=(72-100)/15=-28/15=-1.87
To find the area or percentage between the given value and mean
z=( 100-100)/15= 0/15= 0
How do you find the distance from the given value and the mean?
A number that tells you how many standard deviations from mean of set
Subtract
z=(121-100)/15=21/15= 1.40
True
Divide
z=(72-100)/15=-28/15=-1.87
To find the area or percentage between the given value and mean
z=( 100-100)/15= 0/15= 0
It Is always the value minus the mean, NOT the mean minus the value.
A number that tells you how many standard deviations from mean of set
Subtract
z=(121-100)/15=21/15= 1.40
True
Divide
z=(72-100)/15=-28/15=-1.87
To find the area or percentage between the given value and mean
z=( 100-100)/15= 0/15= 0
How do you find the number of standard deviations that would fit into the distance found?
A number that tells you how many standard deviations from mean of set
Subtract
z=(121-100)/15=21/15= 1.40
True
Divide
z=(72-100)/15=-28/15=-1.87
To find the area or percentage between the given value and mean
z=( 100-100)/15= 0/15= 0
What is a Z-score?
A number that tells you how many standard deviations from mean of set
Subtract
z=(121-100)/15=21/15= 1.40
True
Divide
z=(72-100)/15=-28/15=-1.87
To find the area or percentage between the given value and mean
z=( 100-100)/15= 0/15= 0
The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 72?
A number that tells you how many standard deviations from mean of set
Subtract
z=(121-100)/15=21/15= 1.40
True
Divide
z=(72-100)/15=-28/15=-1.87
To find the area or percentage between the given value and mean
z=( 100-100)/15= 0/15= 0
The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 100?
A number that tells you how many standard deviations from mean of set
Subtract
z=(121-100)/15=21/15= 1.40
True
Divide
z=(72-100)/15=-28/15=-1.87
To find the area or percentage between the given value and mean
z=( 100-100)/15= 0/15= 0
The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 121?
A number that tells you how many standard deviations from mean of set
Subtract
z=(121-100)/15=21/15= 1.40
True
Divide
z=(72-100)/15=-28/15=-1.87
To find the area or percentage between the given value and mean
z=( 100-100)/15= 0/15= 0
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