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The formula for z-scores is: (mean-given)/standard deviation
False
A number that tells you how many standard deviations from mean of set
z=( 100-100)/15= 0/15= 0
To find the area or percentage between the given value and mean
z=(140-100)/15=40/15= 2.67
Divide
Subtract
z=(72-100)/15=-28/15=-1.87
What is a Z-score?
False
A number that tells you how many standard deviations from mean of set
z=( 100-100)/15= 0/15= 0
To find the area or percentage between the given value and mean
z=(140-100)/15=40/15= 2.67
Divide
Subtract
z=(72-100)/15=-28/15=-1.87
The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 100?
False
A number that tells you how many standard deviations from mean of set
z=( 100-100)/15= 0/15= 0
To find the area or percentage between the given value and mean
z=(140-100)/15=40/15= 2.67
Divide
Subtract
z=(72-100)/15=-28/15=-1.87
How do you find the distance from the given value and the mean?
False
A number that tells you how many standard deviations from mean of set
z=( 100-100)/15= 0/15= 0
To find the area or percentage between the given value and mean
z=(140-100)/15=40/15= 2.67
Divide
Subtract
z=(72-100)/15=-28/15=-1.87
The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 72?
False
A number that tells you how many standard deviations from mean of set
z=( 100-100)/15= 0/15= 0
To find the area or percentage between the given value and mean
z=(140-100)/15=40/15= 2.67
Divide
Subtract
z=(72-100)/15=-28/15=-1.87
The Wechsler IQ test have a mean of 100 with a standard deviation of 15. What is the z-score if the IQ is 140?
False
A number that tells you how many standard deviations from mean of set
z=( 100-100)/15= 0/15= 0
To find the area or percentage between the given value and mean
z=(140-100)/15=40/15= 2.67
Divide
Subtract
z=(72-100)/15=-28/15=-1.87
How do you find the number of standard deviations that would fit into the distance found?
False
A number that tells you how many standard deviations from mean of set
z=( 100-100)/15= 0/15= 0
To find the area or percentage between the given value and mean
z=(140-100)/15=40/15= 2.67
Divide
Subtract
z=(72-100)/15=-28/15=-1.87
How is a z-score used?
False
A number that tells you how many standard deviations from mean of set
z=( 100-100)/15= 0/15= 0
To find the area or percentage between the given value and mean
z=(140-100)/15=40/15= 2.67
Divide
Subtract
z=(72-100)/15=-28/15=-1.87
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