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Match it! Select the correct answer from the pull down...Good luck!
i ^2
i
-1
3 + 2i
bi
a
6 + 2i
-i
1
square root (-1) is
i
-1
3 + 2i
bi
a
6 + 2i
-i
1
2+3i + 4 - i
i
-1
3 + 2i
bi
a
6 + 2i
-i
1
z = 3 + 4i, arg of z in which quadrant?
i
-1
3 + 2i
bi
a
6 + 2i
-i
1
z = a + bi, Real part is
i
-1
3 + 2i
bi
a
6 + 2i
-i
1
z = a + bi, imaginary part is
i
-1
3 + 2i
bi
a
6 + 2i
-i
1
The complex number (3 - 2i) is a root of a quadratic equation, write another root
i
-1
3 + 2i
bi
a
6 + 2i
-i
1
i^3
i
-1
3 + 2i
bi
a
6 + 2i
-i
1
Check it!