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Match it! Select the correct answer from the pull down...Good luck!
Power can be calculated by multiplying
$1.20
Joules
Joules / Time
Current x Voltage
Kilowatt-hours
when one light bulb goes out, the other goes out too
current stays the same throughout the circuit
junction point
An air conditioner uses 1000W, and is on for 12 hours in one day. If it costs $0.10 per kWh, how muich does it cost to use the air conditioner for a day?
$1.20
Joules
Joules / Time
Current x Voltage
Kilowatt-hours
when one light bulb goes out, the other goes out too
current stays the same throughout the circuit
junction point
In a series circuit
$1.20
Joules
Joules / Time
Current x Voltage
Kilowatt-hours
when one light bulb goes out, the other goes out too
current stays the same throughout the circuit
junction point
Energy is measured in
$1.20
Joules
Joules / Time
Current x Voltage
Kilowatt-hours
when one light bulb goes out, the other goes out too
current stays the same throughout the circuit
junction point
The point where a parallel circuit branches out is called a
$1.20
Joules
Joules / Time
Current x Voltage
Kilowatt-hours
when one light bulb goes out, the other goes out too
current stays the same throughout the circuit
junction point
In a parallel circuit with 2 light bulbs connected in parallel,
$1.20
Joules
Joules / Time
Current x Voltage
Kilowatt-hours
when one light bulb goes out, the other goes out too
current stays the same throughout the circuit
junction point
BC Hydro bills you according to your usage, measured in
$1.20
Joules
Joules / Time
Current x Voltage
Kilowatt-hours
when one light bulb goes out, the other goes out too
current stays the same throughout the circuit
junction point
Power can be calculated by multiplying
$1.20
Joules
Joules / Time
Current x Voltage
Kilowatt-hours
when one light bulb goes out, the other goes out too
current stays the same throughout the circuit
junction point
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