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An acid is a
12-14
H20 + KCl
-log[H^+]
strong base
strong acid
4.0
green
proton donor
What is the correct equation for pH
12-14
H20 + KCl
-log[H^+]
strong base
strong acid
4.0
green
proton donor
HCl + KOH will form
12-14
H20 + KCl
-log[H^+]
strong base
strong acid
4.0
green
proton donor
The pH of 1.0 x 10^-4 HCl is
12-14
H20 + KCl
-log[H^+]
strong base
strong acid
4.0
green
proton donor
KOH is a
12-14
H20 + KCl
-log[H^+]
strong base
strong acid
4.0
green
proton donor
A strong acid has a pOH of (notice it is pOH and NOT pH) Think pH + pOH = 14
12-14
H20 + KCl
-log[H^+]
strong base
strong acid
4.0
green
proton donor
What color will water have when Universal Indicator is added
12-14
H20 + KCl
-log[H^+]
strong base
strong acid
4.0
green
proton donor
HNO3 is a
12-14
H20 + KCl
-log[H^+]
strong base
strong acid
4.0
green
proton donor
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