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NaOH reacts with FeCl3 to produce a precipitate. If 100 mL of 0.100 M NaOH is added to 100 mL of 0.100 M FeCl3, the concentration of sodium ions in the resulting solution would be
BaCl2
0.183 L
0.015 M
85.2 g
The solution will be acid
Sodium sulfate
0.0500 M
2 L of 0.2 M (NH4)2CO3
If 450 mL of 0.15 M HCl is mixed with 270 mL of 0.10 M Mg(OH)2 are mixed
BaCl2
0.183 L
0.015 M
85.2 g
The solution will be acid
Sodium sulfate
0.0500 M
2 L of 0.2 M (NH4)2CO3
Which will contain the most ions? (total cations and anions)
BaCl2
0.183 L
0.015 M
85.2 g
The solution will be acid
Sodium sulfate
0.0500 M
2 L of 0.2 M (NH4)2CO3
What mass of Na2SO4 is required to prepare 400. mL of 1.50 M Na2SO4 solution?
BaCl2
0.183 L
0.015 M
85.2 g
The solution will be acid
Sodium sulfate
0.0500 M
2 L of 0.2 M (NH4)2CO3
Which reactant is limiting when equal volumes of equal concentrations of strontium nitrate and sodium sulfate are mixed?are
BaCl2
0.183 L
0.015 M
85.2 g
The solution will be acid
Sodium sulfate
0.0500 M
2 L of 0.2 M (NH4)2CO3
25 mL of 1.5 M solution is diluted to 500 mL. 40 mL of the resulting solution is diluted to 200 mL. What is the final concentration?
BaCl2
0.183 L
0.015 M
85.2 g
The solution will be acid
Sodium sulfate
0.0500 M
2 L of 0.2 M (NH4)2CO3
A 500 mL sample of a 0.350 M solution is left open on a lab counter for weeks, after which the concentration of the solution is 0.955 M. What is the new volume of the solution?
BaCl2
0.183 L
0.015 M
85.2 g
The solution will be acid
Sodium sulfate
0.0500 M
2 L of 0.2 M (NH4)2CO3
0.466 g of an unknown metal chloride is dissolved in water. If the resulting metal ions are completely precipitated by the addition of 22.4 mL of 0.1000 M sodium chromate, the unknown substance is
BaCl2
0.183 L
0.015 M
85.2 g
The solution will be acid
Sodium sulfate
0.0500 M
2 L of 0.2 M (NH4)2CO3
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