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Match it! Select the correct answer from the pull down...Good luck!
Create a sequence (5 terms) from the following Explicit Definition: tn = 4n-1 and find t10
28,34,40 an = (an-1) + 6 or an+1 = an + 6
3,7,11,15,19,23,27,31,35,39 and t10 = 39
t41 = 241
an = 4(3)^n-1
3,7,11,15,19 and t10 = 39
an = 5 + 3(n-1)
1.39 x 10^10
an = 3(an-1) or an+1 = 3(an)
Create a sequence (5 terms) from the following Recursive Definition: tn= (tn-1) +4 and t1=3. Also find t10
28,34,40 an = (an-1) + 6 or an+1 = an + 6
3,7,11,15,19,23,27,31,35,39 and t10 = 39
t41 = 241
an = 4(3)^n-1
3,7,11,15,19 and t10 = 39
an = 5 + 3(n-1)
1.39 x 10^10
an = 3(an-1) or an+1 = 3(an)
4,12,36,108 What is the EXPLICIT definition?
28,34,40 an = (an-1) + 6 or an+1 = an + 6
3,7,11,15,19,23,27,31,35,39 and t10 = 39
t41 = 241
an = 4(3)^n-1
3,7,11,15,19 and t10 = 39
an = 5 + 3(n-1)
1.39 x 10^10
an = 3(an-1) or an+1 = 3(an)
Given that a1= 1 and an = 6(n)-5, determine which term, n, of the sequence is 241.
28,34,40 an = (an-1) + 6 or an+1 = an + 6
3,7,11,15,19,23,27,31,35,39 and t10 = 39
t41 = 241
an = 4(3)^n-1
3,7,11,15,19 and t10 = 39
an = 5 + 3(n-1)
1.39 x 10^10
an = 3(an-1) or an+1 = 3(an)
5,8,11,14 What is the EXPLICIT DEFINITION?
28,34,40 an = (an-1) + 6 or an+1 = an + 6
3,7,11,15,19,23,27,31,35,39 and t10 = 39
t41 = 241
an = 4(3)^n-1
3,7,11,15,19 and t10 = 39
an = 5 + 3(n-1)
1.39 x 10^10
an = 3(an-1) or an+1 = 3(an)
4, 10, 16, 22 next 3 numbers: , , RULE:________________________
28,34,40 an = (an-1) + 6 or an+1 = an + 6
3,7,11,15,19,23,27,31,35,39 and t10 = 39
t41 = 241
an = 4(3)^n-1
3,7,11,15,19 and t10 = 39
an = 5 + 3(n-1)
1.39 x 10^10
an = 3(an-1) or an+1 = 3(an)
4,12,36,108 What is the 21 term or t21?
28,34,40 an = (an-1) + 6 or an+1 = an + 6
3,7,11,15,19,23,27,31,35,39 and t10 = 39
t41 = 241
an = 4(3)^n-1
3,7,11,15,19 and t10 = 39
an = 5 + 3(n-1)
1.39 x 10^10
an = 3(an-1) or an+1 = 3(an)
4,12,36,108 What is the RECURSIVE definition?
28,34,40 an = (an-1) + 6 or an+1 = an + 6
3,7,11,15,19,23,27,31,35,39 and t10 = 39
t41 = 241
an = 4(3)^n-1
3,7,11,15,19 and t10 = 39
an = 5 + 3(n-1)
1.39 x 10^10
an = 3(an-1) or an+1 = 3(an)
Check it!