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The conversion of temperatures measured in Kelvin (K) to degrees Fahrenheit, F, is given by the formula F = 9/5(K-273.15) + 32 . Which of the following equations could be used to convert temperatures from degrees Fahrenheit to Kelvin?
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
100/3
K= (5F-160)/9 + 273.15
K= (5F-160)/9 + 273.15
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
4.89
The relationship between density (D) in g/cm3 of liquid mercury and temperature (T) in C is modeled by the equation D = 13.28-0.002T. Which of the following could be a correct interpretation of the 13.628 in the context of the model?
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
100/3
K= (5F-160)/9 + 273.15
K= (5F-160)/9 + 273.15
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
4.89
The relationship between density (D) in g/cm3 of liquid mercury and temperature (T) in C is modeled by the equation D = 13.28-0.002T. If the equation is graphed on a graph plane with T on the x axis and D on the y axis, what is the slope of the line?
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
100/3
K= (5F-160)/9 + 273.15
K= (5F-160)/9 + 273.15
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
4.89
The conversion of temperatures measured in Kelvin (K) to degrees Fahrenheit, F, is given by the formula F = 9/5(K-273.15) + 32 . Which of the following equations could be used to convert temperatures from degrees Fahrenheit to Kelvin?
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
100/3
K= (5F-160)/9 + 273.15
K= (5F-160)/9 + 273.15
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
4.89
The relationship between density (D) in g/cm3 of liquid mercury and temperature (T) in C is modeled by the equation D = 13.28-0.002T. Which of the following could be a correct interpretation of the 13.628 in the context of the model?
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
100/3
K= (5F-160)/9 + 273.15
K= (5F-160)/9 + 273.15
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
4.89
The relationship between density (D) in g/cm3 of liquid mercury and temperature (T) in C is modeled by the equation D = 13.28-0.002T. If the equation is graphed on a graph plane with T on the x axis and D on the y axis, what is the slope of the line?
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
100/3
K= (5F-160)/9 + 273.15
K= (5F-160)/9 + 273.15
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
4.89
Long distance runners often refer to their speed in terms of pace (min/mi). A runner completed a 26.2 mile race in about 2 hrs and 8 minutes. What was the runner's pace for the race?
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
100/3
K= (5F-160)/9 + 273.15
K= (5F-160)/9 + 273.15
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
4.89
Dara drove from home to the airport and then came back home on the same route. Her average speed on the way to the airport was 55 mph and her average going home was 45 mph. If the total driving time was 1 hr 20 min, how far is the airport from home?
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
100/3
K= (5F-160)/9 + 273.15
K= (5F-160)/9 + 273.15
-0.002
The density, in g/cm3, of a sample of liquid mercury at temperature 0 degrees C
4.89
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