Review Game Zone
Games
Test
Preview
Back
Match it!
Match it! Select the correct answer from the pull down...Good luck!
Find the 5 number summary: 9, 20, 4, 18, 4, 18, 20, 9
mean = 8.7; variance = 21.6; standard deviation = 4.6
78
mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.
0.2
minimum 4; first quartile 6.5; median 13.5; third quartile 19; maximum 20
The median best describes the rents because most of the rents were near $740.
The mean is 4, and the standard deviation is about 2.68.
38
What are the mean, variance, and standard deviation of these values? Round to the nearest tenth. 1, 9, 4, 12, 13, 13
mean = 8.7; variance = 21.6; standard deviation = 4.6
78
mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.
0.2
minimum 4; first quartile 6.5; median 13.5; third quartile 19; maximum 20
The median best describes the rents because most of the rents were near $740.
The mean is 4, and the standard deviation is about 2.68.
38
Find the outlier in the set of data. 3.4, 4.8, 3.1, 0.2, 6.9, 5.5, 6.6, 5.1
mean = 8.7; variance = 21.6; standard deviation = 4.6
78
mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.
0.2
minimum 4; first quartile 6.5; median 13.5; third quartile 19; maximum 20
The median best describes the rents because most of the rents were near $740.
The mean is 4, and the standard deviation is about 2.68.
38
The data 1, 5, 8, 5, 1 represent a random sample of the number of days absent from school for five students at Monta Vista High. Find the mean and the standard deviation of the data.
mean = 8.7; variance = 21.6; standard deviation = 4.6
78
mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.
0.2
minimum 4; first quartile 6.5; median 13.5; third quartile 19; maximum 20
The median best describes the rents because most of the rents were near $740.
The mean is 4, and the standard deviation is about 2.68.
38
Find the outlier in the set of data. 17, 13, 16, 18, 38, 14, 21, 24
mean = 8.7; variance = 21.6; standard deviation = 4.6
78
mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.
0.2
minimum 4; first quartile 6.5; median 13.5; third quartile 19; maximum 20
The median best describes the rents because most of the rents were near $740.
The mean is 4, and the standard deviation is about 2.68.
38
Over the first five years of owning her car, Gina drove about 12,700 miles the 1st year, 15,478 miles the 2nd year, 12,675 the 3rd year, 11,850 the 4th year, and 13,075 the 5th year. which one will best predict how many miles Gina will drive the 6th
mean = 8.7; variance = 21.6; standard deviation = 4.6
78
mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.
0.2
minimum 4; first quartile 6.5; median 13.5; third quartile 19; maximum 20
The median best describes the rents because most of the rents were near $740.
The mean is 4, and the standard deviation is about 2.68.
38
Suppose that to make the golf team you need to score no more than 74 on average over 5 games. If you scored 77, 71, 77, and 67 in your first 4 games what is the highest score you can shoot in your 5th game and still make the team?
mean = 8.7; variance = 21.6; standard deviation = 4.6
78
mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.
0.2
minimum 4; first quartile 6.5; median 13.5; third quartile 19; maximum 20
The median best describes the rents because most of the rents were near $740.
The mean is 4, and the standard deviation is about 2.68.
38
The advertised rents for five apartments were $650, $650, $740, $1650, and $820. Which value best describes the monthly rents? Explain. mean = $902, median = $740, mode = $650
mean = 8.7; variance = 21.6; standard deviation = 4.6
78
mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.
0.2
minimum 4; first quartile 6.5; median 13.5; third quartile 19; maximum 20
The median best describes the rents because most of the rents were near $740.
The mean is 4, and the standard deviation is about 2.68.
38
Check it!