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Which equation represents two pounds of nuts which cost x dollars a pound, and four pounds of chocolates which cost $3.
5x + 2y
-2
2
2x-5
-5 + 2x -y
7/2
2x + 12 = 20
y=2
Solve: 20 -3x = 26
5x + 2y
-2
2
2x-5
-5 + 2x -y
7/2
2x + 12 = 20
y=2
solve 3/12 = 2/(y=6)
5x + 2y
-2
2
2x-5
-5 + 2x -y
7/2
2x + 12 = 20
y=2
Simplify 3x-5-x
5x + 2y
-2
2
2x-5
-5 + 2x -y
7/2
2x + 12 = 20
y=2
Solve: 3(5x - 10) = 3x + 12
5x + 2y
-2
2
2x-5
-5 + 2x -y
7/2
2x + 12 = 20
y=2
Solve: 8x + 2x + 6 - 3x = 20
5x + 2y
-2
2
2x-5
-5 + 2x -y
7/2
2x + 12 = 20
y=2
Simplify: -(5 - 2x + y)
5x + 2y
-2
2
2x-5
-5 + 2x -y
7/2
2x + 12 = 20
y=2
Simplify: 4x - 5y + x + 7y
5x + 2y
-2
2
2x-5
-5 + 2x -y
7/2
2x + 12 = 20
y=2
Check it!