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find the mean median and mode for this set of data.
378
43.68
a
.4237
>
16040
79
9 median, 9 mode, 6 mean
423.7 divided 100
378
43.68
a
.4237
>
16040
79
9 median, 9 mode, 6 mean
use mental math to find the product: 160 x 40
378
43.68
a
.4237
>
16040
79
9 median, 9 mode, 6 mean
show what the answer is to this problem: 1/2 and 1/4
378
43.68
a
.4237
>
16040
79
9 median, 9 mode, 6 mean
a
378
43.68
a
.4237
>
16040
79
9 median, 9 mode, 6 mean
;632 divided by eight equals
378
43.68
a
.4237
>
16040
79
9 median, 9 mode, 6 mean
100.00 minus 57.32
378
43.68
a
.4237
>
16040
79
9 median, 9 mode, 6 mean
what is the answer 7x(9x6)=(7xn)x6
378
43.68
a
.4237
>
16040
79
9 median, 9 mode, 6 mean
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