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To solve problems in the stoichiometry unit, we use a method called ...
2.89x10^23 molecules HCl
4.5 moles Fe
limiting reactant
Fe
dimensional analysis
56.4 g FeCl3
3073.4 g iodine gas
122.04 g Na2SiO3 = 1 mole Na2SiO3
What is the mass of 7.29x10^24 molecules of iodine gas?
2.89x10^23 molecules HCl
4.5 moles Fe
limiting reactant
Fe
dimensional analysis
56.4 g FeCl3
3073.4 g iodine gas
122.04 g Na2SiO3 = 1 mole Na2SiO3
Using the balanced equation 3 HCl + 1 Al(OH)3 -- 3 H2O + 1 AlCl3, how many molecules of hydrochloric acid will react with 12.5 grams of aluminum hydroxide?
2.89x10^23 molecules HCl
4.5 moles Fe
limiting reactant
Fe
dimensional analysis
56.4 g FeCl3
3073.4 g iodine gas
122.04 g Na2SiO3 = 1 mole Na2SiO3
Usingthe following balanced equation, 1 Fe3O4 + 4 CO -- 3 Fe + 4 CO2, how many moles of iron will be produced when 6 moles of carbon monoxide are reacted with Fe3O4?
2.89x10^23 molecules HCl
4.5 moles Fe
limiting reactant
Fe
dimensional analysis
56.4 g FeCl3
3073.4 g iodine gas
122.04 g Na2SiO3 = 1 mole Na2SiO3
What is the molar mass of Na2SiO3?
2.89x10^23 molecules HCl
4.5 moles Fe
limiting reactant
Fe
dimensional analysis
56.4 g FeCl3
3073.4 g iodine gas
122.04 g Na2SiO3 = 1 mole Na2SiO3
What is the limiting reagent when 65 grams of iron and 130 grams of chlorine gas react? 2 Fe + 3 Cl2 -- 2 FeCl3
2.89x10^23 molecules HCl
4.5 moles Fe
limiting reactant
Fe
dimensional analysis
56.4 g FeCl3
3073.4 g iodine gas
122.04 g Na2SiO3 = 1 mole Na2SiO3
How many grams of iron (III) chloride is produced when 24 g iron and 37g chlorine gas react? 2 Fe + 3 Cl2 -- 2 FeCl3
2.89x10^23 molecules HCl
4.5 moles Fe
limiting reactant
Fe
dimensional analysis
56.4 g FeCl3
3073.4 g iodine gas
122.04 g Na2SiO3 = 1 mole Na2SiO3
The chemical that is used up first in a chemical reaction is known as ...
2.89x10^23 molecules HCl
4.5 moles Fe
limiting reactant
Fe
dimensional analysis
56.4 g FeCl3
3073.4 g iodine gas
122.04 g Na2SiO3 = 1 mole Na2SiO3
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