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What is the turning point, or vertex, of the parabola whose equation is y = 3x^2 + 6x - 1?
x=-2
33.2 feet
The axis of symmetry is y = -1.
(-1,-4)
y = -x2 + 3x + 5
y = -x^2 -2x - 4
y=2
The height, y, in feet, a ball will reach when thrown in the air is given by the equation y = -16x2 + 30x + 6. Find to the nearest tenth, the maximum height, in feet, the ball wi
x=-2
33.2 feet
The axis of symmetry is y = -1.
(-1,-4)
y = -x2 + 3x + 5
y = -x^2 -2x - 4
y=2
^Will the graph of the parabola y = -2x2 + 4x - 4 open upward or downward?
x=-2
33.2 feet
The axis of symmetry is y = -1.
(-1,-4)
y = -x2 + 3x + 5
y = -x^2 -2x - 4
y=2
Which of the following statements is absolutely NOT true for the parabola y=(x+1)^2
x=-2
33.2 feet
The axis of symmetry is y = -1.
(-1,-4)
y = -x2 + 3x + 5
y = -x^2 -2x - 4
y=2
1. What is the equation of the axis of symmetry for the parabola y=-2x^2? Assume that the turning point (maximum point) is (1,6).
x=-2
33.2 feet
The axis of symmetry is y = -1.
(-1,-4)
y = -x2 + 3x + 5
y = -x^2 -2x - 4
y=2
Which is the equation for the parabola at points (3,0) and (-1,0)?
x=-2
33.2 feet
The axis of symmetry is y = -1.
(-1,-4)
y = -x2 + 3x + 5
y = -x^2 -2x - 4
y=2
What is the equation of the axis of symmetry of the graph y = 3x^2 + 12x - 2 ?
x=-2
33.2 feet
The axis of symmetry is y = -1.
(-1,-4)
y = -x2 + 3x + 5
y = -x^2 -2x - 4
y=2
For which quadratic equation (parabola) is the axis of symmetry x = 3?
x=-2
33.2 feet
The axis of symmetry is y = -1.
(-1,-4)
y = -x2 + 3x + 5
y = -x^2 -2x - 4
y=2
Check it!