# Quadratic Graphs: Question Preview (ID: 9237)

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Given y = 2(x-1)² +1, the equation for its line of symmetry is |
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a) x = 1 | b) x = - 1 | c) y = 1 | d) y= - 1 | |

Given y = 2(x-1)² +1, what is kind of graph is this? |
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a) linear graph | b) parabolic graph | c) parametric graph | d) polar graph | |

Given y = 3x², what will happen to the graph when the coefficient of x² becomes 1? |
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a) The graph will shift upward. | b) The graph will shift downward. | c) The graph will open outward. | d) The graph will squeeze inward or narrower. | |

Which of the following is True of y = x²? |
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a) It has a minimum turning point. | b) It has a maximum turning point. | c) It has no turning point. | d) It has an inflexion point. | |

Given y = ax², what is the shape of the graph when |
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a) A V-shaped curve | b) An inverted V-shaped curve | c) A U-shaped curve | d) An inverted u-shaped curve | |

Given y = 2x², the equation for the line of symmetry for this graph is |
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a) x = - 2 | b) x = 0 | c) y = 2 | d) y = 0 | |

What is the general shape of parabolas? |
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a) circle | b) s-shape | c) straight line | d) U-shape | |

In standard form, a _______ function is written as y = ax² + bx + c |
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a) absolute value | b) cubic | c) linear | d) quadratic | |

Given y = 2(x + 4)² -1, the coordinates of the turning point are |
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a) ( 1, 4) | b) ( -1, - 4) | c) ( 4, 1) | d) ( - 4, - 1) | |

This curve, y=x² - 5x + 7, has what kind of roots? |
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a) equal roots | b) imaginary roots | c) two roots | d) three roots | |

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