# Algebra EOC Prep #1: Question Preview (ID: 14644)

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Scenario A: Write a system of equations to fit this scenario. |
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a) l = 2w - 3 and l + w = 54 | b) l - 3 = 2w and lw = 54 | c) l = 2w - 3 and lw = 54 | d) l - 3 = 2w and l + w = 54 | |

Scenario A: Write a quadratic equation to fit this scenario. |
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a) 2w^2 + 3w - 54 = 0 | b) 2w^2 - 3w - 54 = 0 | c) 2w^2 - 3w + 54 = 0 | d) None of the above | |

Scenario A: Find the dimensions of the photograph. |
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a) w = 3, L = 18 | b) w = 6, L = 6 | c) w = 27, L = 2 | d) w = 6, L = 9 | |

Scenario B: Write a quadratic equation to fit the situation. |
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a) x^2 + 5x + 6 = 30 | b) 3x * 2x = 30 | c) x^2 + 5x + 6 = -30 | d) x^2 + 5x - 6 = 30 | |

Scenario B: What were the dimensions of the original square? |
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a) 6ft by 6ft | b) 6ft by 5ft | c) 3ft by 3ft | d) 5ft by 5ft | |

Scenario B: What are the dimensions of the new rectangle? |
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a) 6ft by 6ft | b) 6ft by 5ft | c) 3ft by 3ft | d) 3ft by 6ft | |

Scenario C: What type of equation should be used to find the dimensions of the garden? |
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a) A system of equations | b) Linear | c) 5m by 12m | d) Quadratic | |

Scenario C: Write a quadratic equation to fit the situation. |
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a) x^2 + 17x + 60 = 0 | b) x^2 + 17x - 60 = 0 | c) (x + 5)(x + 12) = 0 | d) none of the above | |

Scenario C: What were the dimensions of the original garden? |
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a) 8m by 12m | b) 8m by 15m | c) 5m by 15m | d) 5m by 12m | |

Scenario C: What are the dimensions of the new garden? |
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a) 8m by 12m | b) 8m by 15m | c) 5m by 15m | d) 5m by 12m | |

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